4[3+2(x+2)]=

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Solution for 4[3+2(x+2)]= equation:


Simplifying
4[3 + 2(x + 2)] = 0

Reorder the terms:
4[3 + 2(2 + x)] = 0
4[3 + (2 * 2 + x * 2)] = 0
4[3 + (4 + 2x)] = 0

Combine like terms: 3 + 4 = 7
4[7 + 2x] = 0
[7 * 4 + 2x * 4] = 0
[28 + 8x] = 0

Solving
28 + 8x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-28' to each side of the equation.
28 + -28 + 8x = 0 + -28

Combine like terms: 28 + -28 = 0
0 + 8x = 0 + -28
8x = 0 + -28

Combine like terms: 0 + -28 = -28
8x = -28

Divide each side by '8'.
x = -3.5

Simplifying
x = -3.5

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